a, \(\left(\sqrt{3}-1\right).\sqrt{4+2\sqrt{3}}\)
\(=\left(\sqrt{3}-1\right).\sqrt{\left(\sqrt{3}+1\right)^2}\)
\(=\left(\sqrt{3}-1\right).\left|\sqrt{3}+1\right|\)
\(=\left(\sqrt{3}-1\right).\left(\sqrt{3}+1\right)\)
\(=\left(\sqrt{3}\right)^2-1=3-1=2\).
b, Với x không âm ⇔ \(x\ge0\) ta có:
\(5\sqrt{2x}-3\sqrt{8x}+\sqrt{50x}-7\)
\(=5\sqrt{2x}-3\sqrt{2^2.2x}+\sqrt{5^2.2x}-7\)
\(=5\sqrt{2x}-6\sqrt{2x}+5\sqrt{2x}-7\)
\(=\left(5-6+5\right).\sqrt{2x}-7\)
\(=4\sqrt{2x}-7\)
Vậy với \(x\ge0\) thì biểu thức có giá trị \(=4\sqrt{2x}-7\).