Question

Rút gọn A = \(\frac{t^2+4t-12}{\left(t+1\right)\left(t+2\right)-12}\)

Answer 1

A = \(\frac{t^2+6t-2t-12}{t^2+t+2t+2-12}\)

<=> A = \(\frac{t\left(t+6\right)-2\left(t+6\right)}{t^2+3t-10}\)

<=> A = \(\frac{\left(t+6\right)\left(t-2\right)}{t^2-2t+5t-10}\)

<=> A = \(\frac{\left(t+6\right)\left(t-2\right)}{t\left(t-2\right)+5\left(t-2\right)}\)

<=> A = \(\frac{\left(t+6\right)\left(t-2\right)}{\left(t-2\right)\left(t+5\right)}\)

<=> A = \(\frac{t+6}{t+5}\)

Chúc bạn làm bài tốt :)