Question

Rút gọn

a) \(\dfrac{2}{x-3}\)\(\sqrt{\dfrac{x^2-6x+9}{4y^4}}\) (x < 3; y khác 0)

b) \(\dfrac{2}{2x-1}\)\(\sqrt{5x^2\left(1-4x+4x^2\right)}\) (x > 0.5)

Answer 1

a) \(\dfrac{2}{x-3}\sqrt{\dfrac{x^2-6x+9}{4y^4}}=\dfrac{2}{x-3}.\dfrac{3-x}{2y^2}=\dfrac{2.2y^2}{\left(x-3\right)\left(3-x\right)}=-\dfrac{4y^2}{x^2-6x+9}=-\dfrac{2y}{x-3}\)

Answer 2

=\(\dfrac{2}{2x-1}\sqrt{5}x\sqrt[]{\left(1-2x\right)^2}\)

=\(\dfrac{2\sqrt{5}x\left(1-2x\right)}{2x-1}\)

=\(\dfrac{-2\sqrt{5}x\left(2x-1\right)}{2x-1}\)​​

=\(-2\sqrt{5}x\)