x2-8x+16=(x+4)2
3x2-12x=3x(x-4)
MTC: 3x(x-4)2
\(\dfrac{2x}{x^2-8x+16}=\dfrac{2x}{\left(x-4\right)^2}=\dfrac{2x.3x}{\left(x-4\right)^2.3x}=\dfrac{6x^2}{3x\left(x-4\right)^2}\)
\(\dfrac{x}{3x^2-12x}=\dfrac{x}{3x\left(x-4\right)}=\dfrac{x.\left(x-4\right)}{3x\left(x-4\right)\left(x-4\right)}\)