a)
m=1
(1)<=>x^2+x+1-2=0
∆1=1+4=5
x,1,2=(-1±√5)/2
(2)<=>x^2+(1-2)x+8=0
∆2=1-32 <0 vn
b)
x^2+x+m-2(1)
x^2+(m-2)x+8(2)
∆1;1-4m+8=>m≤9/4
∆2: (m-2)^2-4.8≥0
m€(-vc;(2-4√2))U(2+4√2;vc)
dk m(-vc;2-4√2)
z la No chung
(m-3)z+8-m+2=0
m≠3
z=(m-10)/(m-3)
m-3=n
(1)<=>(n-7)^2/n^2+(n-7)/n+n+5=0
(n-7)^2+n(n-7)+n^3+5n^2
n^3+7n^2-21n+49=0
n~2,8
m~5,8>2-2√2 (loai)
khong m thoa man