`(-x-5)(-3x-3)=0`
`<=>` $\left[ \begin{array}{l}-x-5=0\\-3x-3=0\end{array} \right.$
`<=>` $\left[ \begin{array}{l}-x=5\\-3x=-3\end{array} \right.$
`<=>` $\left[ \begin{array}{l}x=-5\\x=-1\end{array} \right.$
Vậy `S={-5,-1}`
Ta có: \(\left(-x-5\right)\left(-3x-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+5=0\\x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=-1\end{matrix}\right.\)
Vậy: S={-5;-1}