Question

Phân tích thành nhân tử

x²+2xy+y²-xz-yz(7x²-14xy+7y²) -29z²5x³-5x²y+10x²-10xy5x²-10xy+5y²-20z²x³+2x²y+y²x-4xx²-7xy+10y²

Answer 1

 1. x² + 2xy + y² - xz - yz

      = ( x² +2xy + y² ) - z ( x + y )

       = ( x + y )² - z ( x + y )

       = ( x + y ) [( x + y ) - z ]

       = ( x + y ) ( x + y - z )

   

Answer 2

1 x^2+2xy+y^2-xz-yz

=(x+y)^2-z(x+y)

=(x+y)(x+y-z)

2 (7x^2-14xy+7^2)-29z^2

=7(x^2-2xy+1)-29z^2

=7(x-1)^2-29z^2

=7(x-1)^2-25z^2-7z^2

=7(x-1-5)(x-1+5)-7z^2

=7(x-6)(x+4)-7z^2

=7((x+6)(x+4)-z^2)

3 5x^3-5x^2y+10x^2-10xy

=5x(x^2-xy+2x-2y)

4 5x^2-10xy+5y^2-20z^2

=5(x^2-2xy+y^2)-20z^2

=5(x+y)^2-20z^2

=5((x+y)^2-4z^2)

=5((x+y-2z)(x+y+2z))