Question

Phân tích thành nhân tử các đa thức sau:

\(x^2-16+2\left(x+4\right)\)

Answer 1

\(=\) \(x^2-16+2x+8\) = \(x^2\) + 2x - 8

= \(x^2\) - 2x + 4x -8

= (x\(^2\)- 2x ) + ( 4x - 8 )

= x( x - 2 ) + 4 ( x - 2 )

= (x + 4 ) ( x - 2 )

Answer 2

\(x^2-16+2\left(x+4\right)\\ =\left(x+4\right)\left(x-4\right)+2\left(x+4\right)\\ =\left(x+4\right)\left(x-4+2\right)\\ =\left(x+4\right)\left(x-2\right)\)

Answer 3

=\(x^2-16+2x+8\)

=\(x^2+2x-8\)

=\(x^2\)-2x+4x-8

=(\(x^2\) -2x)+(4x-8)

=x(x-2)+4(x-2)

=(x-2)(x+4)