Question

phân tích thành nhân tử

a)\(\left(64a^3+125b^3\right)+5b\left(16a^2-25b^2\right)\)

b)\(1-\left(x^2-2xy+y^2\right)\)

c)x\(^6-1\)

Answer 1

a) \(\left(64a^3+125b^3\right)+5b\left(16a^2-25b^2\right)\)

\(=64a^3+125b^3+80a^2b-125b^3\)

\(=64a^3+80a^2b=16a^2.\left(4a+5b\right)\)

b) \(1-\left(x^2-2xy+y^2\right)=1^2-\left(x-y\right)^2\)

\(=\left(1-\left(x-y\right)\right)\left(1+\left(x-y\right)\right)=\left(1-x+y\right)\left(1+x-y\right)\)

c) \(x^6-1=\left(x^3\right)^2-1=\left(x^3-1\right)\left(x^3+1\right)\)

\(\left(x-1\right)\left(x^2+x+1\right)\left(x+1\right)\left(x^2-x+1\right)\)