Question

Phân tích thành nhân tử:

a/\(6x^4-9x^3=.....\)

b/\(x^2y^2z+xy^2z^2+x^2yz^2=.......\)

c/\(2x\left(x-3\right)-\left(3-x\right)^2=.......\)

d/\(y^2\left(x^2+y\right)-zx^2-zy=........\)

Answer 1

a, 6x⁴-9x³=3x³.(2x-3)

b, x²y²z+xy²z²+x²yz²

=xyz.(xy+yz+xz)

c, 2x(x-3)-(3-x)²

=2x(x-3)-(x-3)²

=(x-3)(2x-x+3)

=(x-3)(x+3)

d,y²(x²+y)-zx²-zy

=y²(x²+y)-z(x²+y)

=(x²+y)(y²-z)

Answer 2

bạn nhớ tick và theo dõi mk nhé

Answer 3

a) 6x⁴ - 9x³ = 3x³( 2x - 3 )

b) x²y²z + xy²z² + x²yz² = xyz ( xy + yz + xz )

c) 2x ( x - 3 )-( 3 - x )² = 2x ( x - 3 ) - ( x - 3 )² = ( x - 3 )(2x - 3 + x)

= 3 ( x - 3 )( x - 1 )

d) y²( x² + y ) - zx² - zy=y²( x² + y ) - z( x² + y )=( x² + y )( y² - z )