Question

Phân tích thành nhân tử

A) a^3 - a^2x - ax + xy

B) 7a^2 - 7ax - 9a + 9x

C) xa - xb+ 3a - 3b

Answer 1

a, a³ - a² x - ax + xy

= \(a^2\left(a-x\right)-x\left(a-y\right)\)

b, 7a²-7ax-9a+9x

= \(7a\left(a-x\right)-9\left(a-x\right)\)

= \(\left(7a-9\right)\left(a-x\right)\)

c,xa-xb+3a-3b

= \(x\left(a-b\right)+3\left(a-b\right)\)

= \(\left(x+3\right)\left(a-b\right)\)

Answer 2

câu a sai đề bài hay sao ý

Answer 3

B) 7a² - 7ax - 9a + 9x

=(7a2-7ax)-(9a-9x)

=7a(a-x)-9(a-x)

=(a-x)(7a-9)

C) xa - xb+ 3a - 3b

=(xa-xb)+(3a-3b)

=x(a-b)+3(a-b)

=(a-b)(x+3)

Answer 4

b, 7a²-7ax-9a+9x

<=> (7a²-7ax) -(9a-9x)

<=> 7a(a-x)-9(a-x)

<=>(7a-9)(a-x)

c,xa - xb+ 3a - 3b

<=>(xa-3a)-(xb-3b)

<=>a(x-3)-b(x-3)

<=>(a-b)(x-3)