Question

Phân tích đa thức thành nhân tử:

A=  10x²+ 20xy + 10y - 90.

B=   x³y - 3x²y - 4xy + 12y.

C=   125x³ - 10x² + 2x - 1.

Answer 1

a: Ta có: \(A=10x^2+20xy+10y^2-90\)

\(=10\left(x^2+2xy+y^2-9\right)\)

\(=10\left(x+y-3\right)\left(x+y+3\right)\)

b: Ta có: \(B=x^3y-3x^2y-4xy+12y\)

\(=x^2y\left(x-3\right)-4y\left(x-3\right)\)

\(=y\left(x-3\right)\left(x-2\right)\left(x+2\right)\)

c: Ta có: \(C=125x^3-10x^2+2x-1\)

\(=\left(5x-1\right)\left(25x^2+5x+1\right)-2x\left(5x-1\right)\)

\(=\left(5x-1\right)\left(25x^2+3x+1\right)\)

Answer 2