Question

Phân tích đa thức thành nhân tử:

x⁶ + 1

Answer 1

\(x^6+1\)

\(=x^6-x^4+x^2+x^4-x^2+1\)

\(=x^2\left(x^4-x^2+1\right)+\left(x^4-x^2+1\right)\)

\(=\left(x^2+1\right)\left(x^4-x^2+1\right)\)

Answer 2

x⁶ + 1= (x³)² + (1³)²

= (x³ + 1)²

= [(x + 1)(x² - x + 1)]²

= (x² + 1)(x⁴ - x² + 1)

Answer 3

\(x^6+1=\left(x^2\right)^3+1^3=\left(x^2+1\right)\left(x^2-x^2+1^2\right)=\left(x^2+1\right)\)

Answer 4

\(x^6+1\)

\(=\left(x^2\right)^3+1^3\)

\(=\left(x^2+1\right)\left[\left(x^2\right)^2-x^2+1\right]\)

\(=\left(x^2+1\right)\left(x^4-x^2+1\right)\)

Answer 5

x⁶+1=(x²)³+1³=(x²+1)(x⁴-x².1+1)

=(x²+1)(x⁴-x²+1)

Answer 6

ta có:\(x^6+1=\left(x^2\right)^3+1^3\)

\(=\left(x^2+1\right)\left(x^2-2x+1\right)^2\)

\(=\left(x^2+1\right)\left(x^4-4x^2+1\right)\)