Question

phân tích đa thức thành nhân tử

\(x^5-5x^3+4x\)

Answer 1

x⁵-5x³+4x=x(x⁴-5x²+4)=x(x⁴-x²-4x²+4)=x[x²(x²-1)-4(x²-1)]

=x(x²-1)(x²-4)= x(x-1)(x+1)(x-2)(x+2)

Answer 2

\(x^5-5x^3+4x\)

\(=x^5-x^3-4x^3+4x\)

\(=x\left(x^4-x^2-4x^2+4\right)\)

\(=x\left(x^2-4\right)\left(x^2-1\right)\)

\(=x\left(x+2\right)\left(x-2\right)\left(x+1\right)\left(x-1\right)\)