\(x^4-2x^2+8=x^4+2x^2-4x^2+8=\left(x^2-4\right)\left(x^2+2\right)=\left(x-2\right)\left(x+2\right)\left(x^2+2\right)\)\(\left(x^4-2x^2-8\right):\left(x-2\right)=\left(x+2\right)\left(x^2+2\right)=0\)
\(\Rightarrow x=-2\)
tim x bang cach phan tich da thuc thanh nhan tu
x3-3x2+3x-1=0
phan tich da thuc thanh nhan tu
\(\left(x^2-8\right)^2+36\)
phan tich da thuc thanh nhan tu -25x^6-y^8+10x^3y^4
x^2+14x-48
phan tich da thuc thanh nhan tu
phan tich da thuc thanh nhan tu
x^2-3x+3y-y^2
phan tich da thuc thanh nhan tu
a, x^2+x-6
b,x^4+4
phan tich da thuc thanh nhan tu
\(x^4-x^2+1\)
phan tich da thuc thanh nhan tu :x^5+2x^4+3x^3+2x^2+2x+1
phan tich da thuc thanh nhan tu a. x^3+x+2
b, x^4+5x^3+10x-4
