Question

phan tich da thuc thanh nhan tu a. x^3+x+2

b, x^4+5x^3+10x-4

Answer 1

\(x^3+x+2=\left(x^3+1\right)+\left(x+1\right)\)

\(=\left(x+1\right)\left(x^2-x+1\right)+\left(x+1\right)\)

\(=\left(x+1\right)\left(x^2-x+1+1\right)\)

\(=\left(x+1\right)\left(x^2-x+2\right)\)

\(b,x^4+5x^3+10x-4=\left(x^4-4\right)+\left(5x^3-10x\right)\)\(=\left(x^2+2\right)\left(x^2-2\right)+5x\left(x^2+2\right)\)

\(=\left(x^2+2\right)\left(x^2-2+5x\right)\)