a) \(x^2+8x+16=\left(x+4\right)^2=\left(x+4\right)\left(x+4\right)\)
b) \(x^3-6x^2+12x-8=\left(x-2\right)^3=\left(x-2\right)\left(x-2\right)\left(x-2\right)\)
a) x^2 + 8x +16 = x^2 +2.x.4 +4^2 = (x +4)2
b)x^3 -6x^2 + 12x -8 = x^3 - 3.x^2.2 + 3.x.2^2 - 2^3
=(x-2)3