Giải:
\(a^3-a^2c+a^2b-abc\)
\(=a\left(a^2-ac+ab-bc\right)\)
\(=a\left[\left(a^2-ac\right)+\left(ab-bc\right)\right]\)
\(=a\left[a\left(a-c\right)+b\left(a-c\right)\right]\)
\(=a\left(a-c\right)\left(a+b\right)\)
Chúc bạn học tốt!
\(a^3-a^2c+a^2b-abc\)
\(=a\left(a^2-ac+ab-bc\right)\)
\(=a\left[\left(a^2-ac\right)+\left(ab-bc\right)\right]\)
\(=a\left[a\left(a-c\right)+b\left(a-c\right)\right]\)
\(a\left(a-c\right)\left(a+b\right)\)

