Question

Phân tích đa thức thành nhân tử

a, x² +2xy + y²

b, 2x² + 6x - x - 3

c, 3x² - 2x + 3x + 2

Mọi ng giải hộ mình với ạ 😀

Answer 1

a) (x + y)²

b) 2x² + 6x - x - 3 = 2x(x + 3) - (x + 3) = (x + 3)(2x - 1)

c) 3x² - 2x +3x - 2 = x(3x - 2) + (3x - 2) = (3x - 2)(x + 1)

Answer 2

a,x^2+2xy+y^2=(x+y)^2

b,2x²+6x-x-3 = 2x² - 1x + 6x - 3= x • (2x-1)+ 3 • (2x-1)=(x+3) • (2x-1)

c 3x²+2x+3x+2 = ((3x² + 2x) + 3x) + 2=x(3x+2)+3x+2=(x+1)(3x+2)

(câu c chắc bạn ghi sai đề)

Answer 3

\(a,x^2+2xy+y^2=\left(x+y\right)^2\)

\(b,2x^2+6x-x-3=2x\left(x+3\right)-\left(x+3\right)=\left(x+3\right)\left(2x-1\right)\)

=.= hok tốt!!

Answer 4

\(a,x^2+2xy+y^2\)

\(=\left(x+y\right)^2\)

\(b,2x^2+6x-x-3\)

\(=\left(2x^2-x\right)+\left(6x-3\right)\)

\(=x\left(2x-1\right)+3\left(2x-1\right)\)

\(=\left(x+3\right)\left(2x-1\right)\)