Question

phân tích đa thức thành nhân tử:

6x² + x - 2

Answer 1

\(6x^2+x-2.\)

\(=6x^2+4x-3x-2.\)

\(=\left(6x^2+4x\right)-\left(3x+2\right).\)

\(=2x\left(3x+2\right)-\left(3x+2\right).\)

\(=\left(2x-1\right)\left(3x+2\right).\)

Answer 2

\(6x^2+x-2\)

= \(6x^2+3x-2x+2\)

= \(3x\left(x+1\right)-2\left(x+1\right)\)

= \(\left(3x-2\right)\left(x+1\right)\)

Answer 3

6x^2 +x - 2

=6x^2 + 3x - 2x - 2

= 3x(x+1) - 2(x+1)

= (x+1)(3x-2)