Question

Phân tích đa thức thành nhân tử

3x²+9x-30

Answer 1

3x²+9x-30

=3x²+15x-6x-30

=(3x²-6x)+(15x-30)

=3x(x-2)+15(x-2)

=(3x+15)(x-2)

Answer 2

3x² + 9x - 30

= 3(x² + 3x - 10)

= 3(x² - 2x + 5x - 10)

= 3[x(x - 2) + 5(x - 2)]

= 2(x - 2)(x + 5)

Answer 3

\(3x^2+9x-30\)

\(=3\left(x^2+3x-10\right)\)

\(=3\left(x^2+5x-2x-10\right)\)

\(=3\left[x\left(x+5\right)-2\left(x+5\right)\right]\)

\(=3\left(x+5\right)\left(x-2\right)\)

Answer 4

\(3x^2+9x-30\)

=\((3x^2-6x)+\left(15x-30\right)\)

= 3x (x-2) + 15 ( x-2)

= (3x+ 15) . ( x-2)

Answer 5

3x² +9x -30

=3(x² +3x -10)

=3(x²-2x +5x -10)

=3(x(x-2) +5(x-2))

=3(x-2)(x+5)

Answer 6

3x² + 9x - 30

= 3(x² + 3x - 10)

= 3(x² + 5x - 2x - 10)

= 3[(x² + 5x) - (2x + 10)]

= 3[x(x + 5) - 2(x + 5)]

= 3(x + 5)(x - 2)