Question

Phân tích đa thức thành nhân tử

\(2x^4+3x^3-9x^2-3x+2 \)

\(x^4-3x^3-6x^2+3x+1\)

\(x^4-8x^2-x+12\)

\(x^4-x^3-10x^2+2x+4\)

\((x+2)^4+(x+8)^4-272\)

\((3-x)^4+(4x-x)^4-(7-2x)^4\)

\(2x^4-x^3y+3x^2y^2-xy^3+2x^4\)

Answer 1

a) Ta có: \(2x^4+3x^3-9x^2-3x+2\)

\(=2x^4-2x^3-2x^2+5x^3-5x^2-5x-2x^2+2x+2\)

\(=2x^2\left(x^2-x-1\right)+5x\left(x^2-x-1\right)-2\left(x^2-x-1\right)\)

\(=\left(x^2-x-1\right)\left(2x^2+5x-2\right)\)