Question

Phân tích đa thức thành nhân tử:

(2x-5)^2-64

Answer 1

\(\left(2x-5\right)^2-64\)

\(=4x^2-20x-39\)

\(=\left(2x+3\right)\left(2x-13\right)\)

Answer 2

\(\left(2x-5\right)^2-64=\left(2x-5\right)^2-8^2=\left(2x-5-8\right)\left(2x-5+8\right)=\left(2x-13\right)\left(2x+3\right)\)

Answer 3

(2x-5)² -64

=(2x-5)²- 8² = ( 2x-5-8).(2x-5+8) = ( 2x-13).(2x+3)

Answer 4

\(\left(2x-5\right)^2-64\)

\(=4x^2-20x-39\)

\(=\left(2x+3\right)\left(2x-13\right)\)