Question

Phân tích đa thức thành nhân tử

11, 8a³-12a²+6a-1

12, x³+12x²+48x+64

13, a³+b³+c³-3abc

14, a³-b³+c³+3abc

15, 4x⁴+1

16, 4x⁴+y⁴

17, x⁴+324

18, x⁵+x+1

19, x¹¹+x+1

20, (x-3)(x-5)(x-6)(x-10)-24x²

Answer 1

11, 8a³-12a²+6a-1 = ( 2a - 1 )\(^3\)

12, x³+12x²+48x+64 = ( x + 4 )\(^3\)

13, a³+b³+c³-3abc = ( a + b + c ) ( a\(^2\) + b\(^2\) +c\(^2\) - ab - bc - ca )

15, 4x⁴+1 = ( 2x\(^2\) + 1 ) ( 2x\(^2\) - 1 )

Answer 2

17, = (x\(^4\)+36x\(^2\)+324)-36x\(^2\)= (x+18)\(^2\)-36x\(^2\) = (x+18-36)(x+18+36)=(x-18)(x+54).

18, = x^5+x^4+x^3-x^4-x^3-x^2+x+1-x^2 = x^3(x+1)\(^2\)-x^2+(x+1)\(^2\)+(x+1)\(^2\) = (x\(^3\)-x\(^2\)+1)(x+1)\(^2\) (19 cmtt)