Question

Phân tích đa thức sau thành nhân tử

x^2 - 6x +5

x^2 + 5x -6

x^2-5x + 4

Answer 1

a)x^2-6x+5

=x^2-x-(5x-5)

=x(x-1)-5.(x-1)

=(x-5)(x-1)

b)x^2+5x-6

=x^2-x+6x-6

=x(x-1)+6(x-1)

=(x+6)(x-1)

c)x^2-5x+4

=x^2-x-(4x-4)

=x(x-1)-4(x-1)

=(x-4)(x-1)

Answer 2

a) \(x^2-6x+5=\left(x-1\right)\left(x-5\right)\)

b) \(x^2+5x-6=\left(x-1\right)\left(x+6\right)\)

c) \(x^2-5x+4=\left(x-1\right)\left(x+6\right)\)

Answer 3

a) \(x^2-6x+5=\left(x-1\right)\left(x-5\right)\)

b) \(x^2+5x-6=\left(x-1\right)\left(x+6\right)\)

c) \(x^2-5x+4=\left(x-1\right)\left(x-4\right)\)