Question

phân tích đa thức sau thành nhân tử:

a) x²+2x-y²+1

b) x²+3x-y²+3y

c) 3(x+3)-x²+9

Giúp mih vs mih đag cần gấp

Answer 1

phân tích đa thức sau thành nhân tử:

a) x²+2x-y²+1

=x\(^2\)+2x+1-y\(^2\)

=(x+1)\(^2\)-y\(^2\)

=(x+1-y)(x+1+y)

b) x²+3x-y²+3y

=x\(^2\)-y\(^2\)+3x+3y

=(x-y)(x+y)+3(x+y)

=(x+y)(x-y+3)

c) 3(x+3)-x²+9

=3(x+3)-(x\(^2\)-3\(^2\))

=3(x+3)-(x-3)(x+3)

=(x+3)[3-(x-3)]

=(x+3)(3-x+3)

Answer 2

a) x2+2x-y2+1

=x+2x+1-y

=(x+1)-y

=(x+1-y)(x+1+y)

b) x2+3x-y2+3y

=x-y+3x+3y

=(x-y)(x+y)+3(x+y)

=(x+y)(x-y+3)

c) 3(x+3)-x2+9

=3(x+3)-(x-3)

=3(x+3)-(x-3)(x+3)

=(x+3)[3-(x-3)]

=(x+3)(3-x+3)

=(x+3)(6-x)