\(1.x^6-y^6\\ =\left(x^3\right)^2-\left(y^3\right)^2\\ =\left(x^3-y^3\right)\left(x^3+y^3\right)\\ =\left(x-y\right)\left(x^2+xy+y^2\right)\left(x+y\right)\left(x^2-xy+y^2\right)\)
\(2.x^2+5x-6\\ =x^2-x+6x-6\\ =x\left(x-1\right)+6\left(x-1\right)\\ =\left(x+6\right)\left(x-1\right)\)
\(3.7x-6x^2-2\\ =-6\left(x^2-\frac{7}{6}x+\frac{1}{3}\right)\\ =x^2-\frac{7}{6}x+\frac{1}{3}\\ =x^2-\frac{1}{2}x-\frac{2}{3}x+\frac{1}{3}\\ =x\left(x-\frac{1}{2}\right)-\frac{2}{3}\left(x-\frac{1}{2}\right)\\ =\left(x-\frac{2}{3}\right)\left(x-\frac{1}{2}\right)\)
