Question

 

phân tích các đa thức sau thành nhân tử:

a,3x²-6xy+3y²

b,xy-9x+y-9

Answer 1

a,3x²-6xy+3y²

= 3(x²- 2xy+ y²)

= 3(x- y)²

b,xy-9x+y-9

= (xy+ y)- (9x+ 9)

= y(x+ 1)- 9(x+ 1)

= (x+1)(y- 9)

Chúc bạn học tốt

Answer 2

a,\(3x^2-6xy+3y^2\)

=\(3\left(x^2-2xy+y^2\right)\)

=\(3\left(x-y\right)^2\)

b,xy-9x+y-9

=\(\left(xy+y\right)-\left(9x+9\right)\)

=\(y\left(x+1\right)-9\left(x+1\right)\)

=\(\left(x+1\right)\left(y-9\right)\)

Answer 3

a) Ta có: \(3x^2-6xy+3y^2\)

\(=3\left(x^2-2xy+y^2\right)\)

\(=3\left(x-y\right)^2\)

b) Ta có: \(xy-9x+y-9\)

\(=x\left(y-9\right)+\left(y-9\right)\)

\(=\left(y-9\right)\left(x+1\right)\)

Answer 4

a, = 3( x²- 2xy- y²)

= 3(x-y)²

b, = (xy + y) - (9x + 9)

= y(x+1) + 9 (x+1)

= (x+1) (y+9)