Question

Phân tích các đa thức sau thành nhân tử:

\(i,x^2+y^2-2xy-4x+4y\)

\(a,6x^2+11x+3\)

Answer 1

i) x² + y² - 2xy - 4x + 4y

= (x² - 2xy + y²) - (4x - 4y)

= (x - y)² - 4.(x - y)

= (x - y).(x - y - 4)

a) \(6x^2+11x+3\)

\(=6x^2+2x+9x+3\)

\(=2x.\left(x+\dfrac{1}{3}\right)+3.\left(x+\dfrac{1}{3}\right)\)

\(=\left(x+\dfrac{1}{3}\right).\left(2x+3\right)\)

Answer 2

i, \(x^2+y^2-2xy-4x+4y\)

\(=\left(x-y\right)^2-\left(4x-4y\right)\)

\(=\left(x-y\right)^2-\left[4\left(x-y\right)\right]\)

\(=\left(x-y\right)\left(x-y-4\right)\)