\(C_4H_{10}+\frac{13}{2}O_2\rightarrow4CO_2+5H_2O\)
\(n_{CO_2}=0,05mol\Rightarrow\left\{{}\begin{matrix}n_{O_2}=0,08125mol\\n_{C_4H_{10}}=0,2mol\\n_{H_2O}=0,0625mol\end{matrix}\right.\)
\(V_{O_2}=0,08125\cdot22,4=1,82mol\)
\(m_{C_4H_{10}}=0,2\cdot58=11,6gam\)
\(m_{H_2O}=0,2\cdot18=3,6gam\)