\(n_{CO_2}=\dfrac{5,6}{22,4}=0,25\left(mol\right)\)
PTHH:
\(CaCO_3-t^o->CaO+CO_2\)
x.........................................x....................x
\(BaCO_3-t^o->BaO+CO_2\)
y........................................y.......................y
Gọi x, y lần lượt là số mol của \(CaCO_3;BaCO_3\)
Ta có hệ PT:
\(\left\{{}\begin{matrix}56x+153y=29,85\\x+y=0,25\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0,09\\y=0,16\end{matrix}\right.\)
=> \(m_{CaCO_3}=0,09.100=9\left(g\right)\)
=> \(m_{BaCO_3}=0,16.197=31,52\left(g\right)\)
=> \(\left\{{}\begin{matrix}\%m_{CaCO_3}=\dfrac{9}{\left(9+31,52\right)}.100\%=22,21\%\\\%m_{BaCO_3}=100\%-22,21\%=77,79\%\end{matrix}\right.\)
