PTHH: \(2KMnO_4\underrightarrow{t^o}K_2MnO_4+MnO_2+O_2\\ 1,5mol\leftarrow0,75mol:0,75mol:0,75mol\)
\(4P+5O_2\underrightarrow{t^o}2P_2O_5\\ 0,6mol:0,75mol\leftarrow0,3\left(mol\right)\)
\(n_{P_2O_5}=\dfrac{42,6}{142}=0,3\left(mol\right)\)
\(m_{KMnO_4}=1,5.158=237\left(g\right)\)
Hay a = 237
PTHH:
\(2MnO_4-t^o->KMnO_4+MnO_2+O_2\left(1\right)\)
\(4P+5O_2-t^o->2P_2O_5\left(2\right)\)
Ta có: \(n_{P_2O_5}=\dfrac{42,6}{142}=0,3\left(mol\right)\)
Theo PTHH (2):
\(n_{O_2}=\dfrac{5}{2}n_{P_2O_5}=0,75\left(mol\right)\)
Theo PTHH (1):
\(n_{KMnO_4}=2n_{O_2}=1,5\left(mol\right)\)
\(\Rightarrow m_{KMnO_4}=1,5.158=237\left(g\right)\)
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