
Qua điểm C kẻ tia CM//AB//ED
CM//AB
=>\(\widehat{ACM}+\widehat{CAB}=180^0\)(hai góc trong cùng phía)
=>\(\widehat{ACM}=180^0-118^0=62^0\)
CM//ED
=>\(\widehat{MCD}=\widehat{CDE}\)(hai góc so le trong)
=>\(\widehat{MCD}=50^0\)
\(\widehat{ACD}=\widehat{ACM}+\widehat{DCM}\)
\(=50^0+62^0=112^0\)




