Ta có : \(n-3⋮n^2+4\)
\(\Rightarrow\left(n-3\right)\left(n+3\right)⋮n^2+4\)
\(\Rightarrow n^2-9⋮n^2+4\)
\(\Rightarrow\left(n^2+4++\right)-13⋮n^2+4\)
\(\Rightarrow n^2+4\inƯ\left(13\right)=\left\{\pm1;\pm13\right\}\)
\(n^2+4\in\left\{1;-1;13;-13\right\}\)
\(n^3-3\) (I) \(-5\) (I) \(9-17\) (I)
Vậy \(n\in\left\{\pm3\right\}\)