3cm = 0,03m
xét \(\Delta ABO\) và \(\Delta A'B'O\left(gg\right)\)
=> \(\dfrac{AB}{A'B'}=\dfrac{OA}{OA'}\Leftrightarrow OA'=\dfrac{2.0,03}{1,2}=0,05m\)
AA' = 2 + 0,05 = 2,05m
b, xét \(\Delta IF'O\) và \(\Delta B'F'A'\left(gg\right)\)
\(\Rightarrow\dfrac{F'O}{A'F'}=\dfrac{OI}{A'B'}\Leftrightarrow\dfrac{OF'}{OA'-OF'}=\dfrac{AB}{A'B'}\)
\(\Rightarrow OF'\approx0,05m\)