Đổi: \(2m\text{/}s=7,2km\text{/}h\)
Ta có: \(\left\{{}\begin{matrix}t_1=\dfrac{S_1}{v_1}=\dfrac{3}{7,2}=\dfrac{5}{12}\left(h\right)\\S_2=v_2\cdot t_2=0,5\cdot3,9=1,95\left(km\right)\end{matrix}\right.\)
\(\Rightarrow v_{tb}=\dfrac{S_1+S_2}{t_1+t_2}=\dfrac{3+1,95}{\dfrac{5}{12}+0,5}=5,4\left(km\text{/}h\right)\)
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