\(C_3H_4\left(0,1\right)+4O_2-t^o->3CO_2\left(0,3\right)+2H_2O\left(0,2\right)\) (1)
\(C_xH_y\left(0,2\right)+\left(x+\dfrac{y}{4}\right)O_2-t^o->xCO_2\left(0,6\right)+\dfrac{y}{2}H_2O\left(0,6\right)\) (2)
\(n_{CO2}=0,9\left(mol\right);n_{H2O}=0,8\left(mol\right);n_{C_xH_y}=0,2\left(mol\right)\)
Ta thấy: \(C_xH_y\) cháy cho \(n_{CO_2}=n_{H_2O}\)
=> CTDC: \(C_nH_{2n}\)
Số C = \(\dfrac{n_{CO_2}}{n_{C_xH_y}}=\dfrac{0,6}{0,2}=3\)
=> CTPT: \(C_3H_6\)
CTCT: \(CH_2=CH-CH_3;\)
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