\(n_{H_2}=\dfrac{10.08}{22.4}=0.45\left(mol\right)\)
\(Đăt:n_{CO_2}=3a\left(mol\right),n_{H_2O}=4a\left(mol\right)\)
\(BTKL:\)
\(6+0.45\cdot32=3a\cdot44+4a\cdot18\)
\(\Rightarrow a=0.1\)
\(m_O=6-0.3\cdot12-0.4\cdot2=1.6\left(g\right)\)
\(n_O=\dfrac{1.6}{16}=0.1\left(mol\right)\)
\(CT:C_xH_yO_z\)
\(x:y:z=0.3:0.8:0.1=3:8:1\)
\(CTPT:C_3H_8O\)