\(9x^2-72x=0\)
\(\Leftrightarrow9x\left(x-8\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}9x=0\\x-8=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=8\end{matrix}\right.\)
Vậy..
\(9x^2-72x=0\)
\(\Rightarrow9x.\left(x-8\right)=0\)
\(\Rightarrow\left\{{}\begin{matrix}9x=0\\x-8=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0\\x=8\end{matrix}\right.\)
Vậy \(x\in\left\{0;8\right\}\)
Chúc bạn học tốt!!!
\(9x^2-72x=0\)
\(\Rightarrow9x\left(x-8\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}9x=0\\x-8=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=8\end{matrix}\right.\)
\(\Rightarrow x_1=0;x_2=8\)
9x2 - 72x = 0
9x2-9x.8=0
9.( x2-x.8)=0
=> x2-x.8=0
=>x.x-x.8=0
=> x.(x-8)=0
=> x=0 hoặc x-8=0
=> x=0 hoặc x=8
Vậy x=8 hoặc x-0
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\(9x^2-72x=0\)
\(\Leftrightarrow x\left(9x-72\right)=0\)
\(\Leftrightarrow x=0\)
\(\Leftrightarrow9x-72=0\Rightarrow9x=72\Rightarrow x=8\)