viết lại đề nhé
suy ra M=\(\frac{\left(2-x\right)^2}{\left(x-1\right)^2\left(2-x\right)^2}+\frac{\left(x-1\right)^2}{\left(x-1\right)^2\left(2-x\right)^2}+\frac{1}{\left(x-1\right)^2\left(2-x\right)^2}\)
=\(\frac{\left(2-x\right)^2+\left(x-1\right)^2+1}{\left(x-1\right)^2\left(2-x\right)^2}\)
suy ra \(\left(2-x\right)^2+\left(x-1\right)^2+1>hoặc=1\)
vậy MinM=1 khi 2-x=x-1