Question

Mb đang onl giúp mik vs nha! Cần gấp Y_Y !!!

Answer 1

Câu 6:a)\(Fe+2HCl\rightarrow FeCl_2+H_2\)

b)\(n_{H_2}:\dfrac{5,6}{22,4}=0,25\left(mol\right)\)

\(Fe+2HCl\rightarrow FeCl_2+H_2\)

1...............2...........................1(mol)

0,25...........0,5,,,,,,,,,,,,,,,,,,,,,,0,25(mol)

\(m_{Fe}:56.0,25=14\left(g\right)\)

c)\(m_{HCl}:36,5.0,5=18,25\)

d)\(n_{CuO}:\dfrac{8}{80}=0,1\left(mol\right)\)

\(H_2+CuO\rightarrow Cu+H_2O\)

1.............1...........1..............(mol)

0,1........0,1..........0,1............(mol)

=>Hidro dư

\(m_{Cu}:0,1.64=6,4\left(g\right)\)

Answer 2

Câu 5:

a)\(Mg+2HCl\rightarrow MgCl_2+H_2\)

b)\(n_{Mg}:\dfrac{3,6}{24}=0,15\left(mol\right)\)

\(Mg+2HCl\rightarrow MgCl_2+H_2\)

1..............2...............1.............1(mol)

0,15..........0,3............0,15.......0,15(mol)

\(m_{MgCl_2}:0,15.95=14,25\left(g\right)\)

\(V_{H_2}:0,15.22,4=3,36\left(l\right)\)

c)\(m_{HCl}:0,3.36,5=10,95\left(g\right)\)

d)\(n_{CuO}:\dfrac{16}{80}=0,2\left(mol\right)\)

\(H_2+CuO\rightarrow Cu+H_2O\)

1.............1..........1..............(mol)

0,15........0,15......0,15.........(mol)

\(m_{Cu}:0,15.65=9,75\left(g\right)\)

\(m_{CuO}dư:\left(0,2-0,15\right).80=4\left(g\right)\)