Đèn sáng bthường
\(\Rightarrow U_{đ,ĐM}=U_đ=220V\\ P_{đ,ĐM\left(hoa\right)}=P_{đ\left(hoa\right)}=25W\)
\(I_đ=\dfrac{P_{đ\left(hoa\right)}}{U_đ}=\dfrac{25}{220}=\dfrac{5}{44}A\\ Vì.ĐntR_b\rightarrow I_đ=I_b=\dfrac{5}{44}A\\ U_b=U-U_đ=270-220=50V\\ R_b=\dfrac{U_b}{I_b}=\dfrac{50}{\dfrac{5}{44}}=440\Omega\)