Đặt \(A=2^{2009}+2^{2008}+...+2+2^0\)
\(=1+2+...+2^{2008}+2^{2009}\)
\(\Rightarrow2A=2+2^2+...+2^{2010}\)
\(\Rightarrow2A-A=\left(2+2^2+...+2^{2010}\right)-\left(1+2+...+2^{2009}\right)\)
\(\Rightarrow A=2^{2010}-1\)
\(\Rightarrow M=2^{2010}-\left(2^{2010}-1\right)\)
\(=2^{2010}-2^{2010}+1=1\)
Vậy M = 1
tính
M = \(2^{2010}-\left(2^{2009}+2^{2008}+...+2^1+2^0\right)\)
Tính :
\(M=2^{2010}-\left(2^{2009}+2^{2008}+....+2^1+2^0\right)\)
Tính nhanh hoặc tính hợp lí:
\(T=2^{2010}-\left(2^{2009}+2^{2008}+...+2^1+2^0\right)\)
Giúp mik gấp nha
Tính M=\(2^{2010}-(2^{2009}+2^{2008}+...+2^1+2^0)\)
Rút gọn :
P = 2\(^{2010}\) - 2\(^{2009}\) - 2\(^{2008}\) -...- 2\(^1\) - 1
Giúp mìnk vs nha các bn chiều nay mìnk đi học rùi !
tính:
a) \(\left(2^{-1}+3^{-1}\right):\left(2^{-1}-3^{-1}\right)+\left(2^{-1}.2^0\right):2^3\)
b) \(\left(-\dfrac{1}{3}\right)^{-1}-\left(-\dfrac{6}{7}\right)^0+\left(\dfrac{1}{2}\right)^2:2\)
c) \(\left[\left(0,1\right)^2\right]^0+\left[\left(\dfrac{1}{7}\right)^{-1}\right]^2.\dfrac{1}{49}.\left[\left(2^2\right)^3:2^5\right]\)
giúp mk vs các bn mk dg cần gấp lm
2 / tìm tính
a/\(\dfrac{2^3.6^2}{3^2.4^2}\)=
b/\(\left(\dfrac{3}{2}\right)^{-2+}\dfrac{1}{3}.\left(\dfrac{3}{4}\right)^{-1}+0,\left(3\right)\)=
c/\(\left(\dfrac{5}{3}\right)^{-2}+\dfrac{-1}{5}-0,2\)=
B1: Tìm x,y
a,\(\left|x-2\right|+\left|y-1\right|=0\)
b,\(\left|2-3x\right|+\left|2y+1\right|=0\)
B2: Tìm x, biết
a,\(\left|x-3\right|=3-x\)
b,\(\left|2x+1\right|+x=4\)
c,\(\left|3-x\right|+x-2=3\)
Tìm x,y \(\in\) N biết :25-\(y^2=8\cdot\left(x-2009\right)^2\)
