Question

lm giúp mk vs

Answer 1

\(\left|x-2\right|=2\)

\(\Rightarrow x-2=2\) hoặc \(x-2=-2\)

TH1:\(x-2=2\)

\(x=2+2\)

\(x=4\)

TH2:\(x-1=-2\)

\(x=-2+2\)

\(x=0\)

Vậy: \(x=2\) hoặc \(x=4\)

Answer 2

\(\left|x-2\right|=2\)

\(\Rightarrow x-2=2\) hoặc \(x-2=-2\)

+) \(x-2=2\Rightarrow x=4\)

+) \(x-2=-2\Rightarrow x=0\)

Vậy \(x\in\left\{4;0\right\}\)

Answer 3

Theo bài ra ta có: \(\left|x-2\right|=2\)

=>\(\left[\begin{array}{nghiempt}x-2=2\\x-2=-2\end{array}\right.\)=>\(\left[\begin{array}{nghiempt}x=2+2\\x=-2+2\end{array}\right.\)=>\(\left[\begin{array}{nghiempt}x=4\\x=0\end{array}\right.\)

Vậy xϵ\(\left\{0;4\right\}\)