`(x+1)^2=4(x^2-2x+1)^2`
`<=> (x+1)^2=[2(x-1)]^2`
`<=> (x+1)^2=(2x-2)^2`
`<=> (x+1+2x-2)(x+1-2x+2)=0`
`<=>(3x-1)(-x+3)=0`
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=3\end{matrix}\right.\)
Vậy `S={1/3 ; 3}`.
1. \(^{x^3+x^2+x+1=0}\)
2. \(\left(2x-4\right)\left(3x+1\right)+\left(x-2\right)^2=0\)
3.\(x^2-5x+6=0\)
4. \(x^2-x-6=0\)
5. \(2x^2-3x=4\left(3-2x\right)\)
6. \(3\left(x-11\right)-2\left(x+11\right)=2011\)
7. \(\left(x-4\right)^2-\left(x+2\right)\left(x-6\right)=0\)
8. \(\left(x^2-9\right)\left(x+2\right)=0\)
9.\(\left(2x-1\right)^2=4x\left(x-1\right)\)
10. \(6\left(x+2\right)-5x=15\)
Bài 1 giải các phương trình sau
a, \(\frac{5\left(1-2x\right)}{3}+\frac{x}{2}=\frac{3\left(x-5\right)}{4}-2\)
b, \(\left(x+2\right)^2+\left(x-1\right)\left(x+3\right)=2\left(x-4\right)\left(x+4\right)\)
c, \(\frac{3}{x-1}=\frac{3x+2}{1-x^2}-\frac{4}{x+1}\)
d, \(\frac{1}{x+1}+\frac{2x^2+1}{x^3+1}+\frac{2x^3-2x^2}{x^2-x+1}=2x\)
Bài 2 : Giải phương trình \(x^4+3x^3+6x+4=0\)
các bạn ơi ! giúp mik với đi ! mai kt rồi
4,\(\dfrac{x+1}{3}\)+\(\dfrac{3\left(2x+1\right)}{4}\)=\(\dfrac{2x+3\left(x+1\right)}{6}\)+\(\dfrac{7+12x}{12}\)
5,\(\dfrac{2x}{3}\)+\(\dfrac{2x-1}{6}\)=4-\(\dfrac{x}{3}\)
6,\(\dfrac{x-1}{2}\)+\(\dfrac{x-1}{4}\)=1-\(\dfrac{2\left(x-1\right)}{3}\)
1,\(\dfrac{5\left(x-1\right)+2}{6}\)-\(\dfrac{7x-1}{4x}\)=\(\dfrac{2\left(2x+1\right)}{7}\)-5
2,\(\dfrac{3\left(x-3\right)}{4}\)+\(\dfrac{4x-10,5}{10}\)=\(\dfrac{3 \left(x+1\right)}{5}\)+6
3,\(\dfrac{2\left(3x+1\right)+1}{4}\)-5=\(\dfrac{2\left(3x-1\right)}{5}\)-\(\dfrac{3x+2}{10}\)
Diễn giải ra cho em với ạ!Em cảm ơn
Giaỉ các PT:
a) \(\left(x^2+1\right)^2=4\left(2x-1\right)\)
b) x(x+1)(x+2)(x+3)=24
c)\(\left(12x+7\right)^2\left(3x+2\right)\left(2x+1\right)=3\)
d)\(\left(x^2-9\right)^2=12x+1\)
e)\(\left(x-1\right)^5+\left(x+3\right)^5=242\left(x+1\right)\)
Giup mk vs mn
Giải các phương trình sau :
a) \(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)
b) \(\dfrac{3\left(x-3\right)}{4}+\dfrac{4x-10,5}{10}=\dfrac{3\left(x+1\right)}{5}+6\)
c) \(\dfrac{2\left(3x+1\right)+1}{4}-5=\dfrac{2\left(3x-1\right)}{5}-\dfrac{3x+2}{10}\)
d) \(\dfrac{x+1}{3}+\dfrac{3\left(2x+1\right)}{4}=\dfrac{2x+3\left(x+1\right)}{6}+\dfrac{7+12x}{12}\)
tìm n của phương trình \(x^2-\dfrac{2n-2x}{4}-2x+5n=x^3-9x^2+10\)
có nghiệm bằng \(\dfrac{1}{3}\)của phương trình \(\left(x+1\right)\left(x+3\right)=x\left(x-3\right)+24\)
giải phương trình
a) \(\left(5x+2\right)\left(x-7\right)=0\)
b) \(\left(x^2-1\right)\left(x+3\right)=0\)
c) \(x^2-x-6=0\)
d) \(x^2+x-12=0\)
e) \(15\left(x+9\right)\left(x-3\right)\left(x+21\right)=0\)
g) \(\left(x^2+1\right)\left(x^2+4x+4\right)=0\)
i) \(x^4+2x^3-2x^2+2x-3=0\)
h) \(x^2+5x+6=0\)
Tìm các giá trị của \(x\) sao cho hai biểu thức A và B cho sau đây có giá trị bằng nhau :
a) \(A=\left(x-3\right)\left(x+4\right)-2\left(3x-2\right)\) \(B=\left(x-4\right)^2\)
b) \(A=\left(x+2\right)\left(x-2\right)+3x^2\) \(B=\left(2x+1\right)^2+2x\)
c) \(A=\left(x-1\right)\left(x^2+x+1\right)-2x\) \(B=x\left(x-1\right)\left(x+1\right)\)
d) \(A=\left(x+1\right)^2-\left(x-2\right)^3\) \(B=\left(3x-1\right)\left(3x+1\right)\)
