\(\left(\dfrac{4}{3}\right)^{5x-2}=\dfrac{64}{27}\)
\(\Rightarrow\left(\dfrac{4}{3}\right)^{5x-2}=\left(\dfrac{4}{3}\right)^3\)
\(\Rightarrow5x-2=3\)
\(\Rightarrow5x=3+2\)
\(\Rightarrow5x=5\)
\(\Rightarrow x=5:5\)
\(\Rightarrow x=1\)
Vậy \(x=1\)