Question

\(\left(\dfrac{2}{5}\right)^2+5\dfrac{1}{2}.\left(4,5-2\right)+\dfrac{2^3}{\left(-4\right)}+2008^0\)

Answer 1

\(\left(\dfrac{2}{5}\right)^2+5\dfrac{1}{2}.\left(4,5-2\right)+\dfrac{2^3}{\left(-4\right)}+2008^0\)

\(=\dfrac{4}{25}+\dfrac{11}{2}\left(4,5-2\right)+\left(-2\right)+1\)

\(=\dfrac{4}{25}+\dfrac{99}{4}-11-2+1\)

\(=24,91-12\)

\(=12,91\)

Answer 2

Bài giải nè bạn:

\(\left(\dfrac{2}{5}\right)^2+5\dfrac{1}{2}.\left(4,5-2\right)+\dfrac{2^3}{\left(-4\right)}+2008^0\)

\(=\dfrac{4}{25}+\dfrac{11}{2}.\left(2,5\right)+\dfrac{8}{\left(-4\right)}+2008^0\)

\(=0,16+13,75+\left(-2\right)+1\)

\(=12,91\)

Thấy hay thì hảy cho 1 tick nhé! mơn bạn!