\(\left[\left(\dfrac{2}{5}\right)^2-1,16\right]:\left[\left(3\dfrac{1}{2}-3\dfrac{2}{3}\right):\dfrac{1}{14}\right].\sqrt{\dfrac{1}{9}}\)
=\(\left[0,16-1,16\right]:\left[\left(\dfrac{-1}{6}\right):\dfrac{1}{14}\right].\dfrac{1}{3}\)
=\(\left(-1\right):\left(\dfrac{-7}{3}\right).\dfrac{1}{3}\)
=