Question

\(\left(\dfrac{1}{4}-1\right).\left(\dfrac{1}{5}-1\right).\left(\dfrac{1}{6}-1\right)...\left(\dfrac{1}{2000}-1\right).\left(\dfrac{1}{2001}-1\right)\)

Mn giúp mk đi mk cần gấp lắm làm ơn !

Trần Đăng NhấtAkai HarumaHồng Phúc Nguyễnnguyen van tuan

Answer 1

\(\left(\dfrac{1}{4}-1\right)\left(\dfrac{1}{5}-1\right)\left(\dfrac{1}{6}-1\right)....\left(\dfrac{1}{2000}-1\right)\left(\dfrac{1}{2001}-1\right)\)

\(=\dfrac{-3}{4}.\dfrac{-4}{5}.\dfrac{-5}{6}....\dfrac{-1999}{2000}.\dfrac{-2000}{2001}\)

\(=\dfrac{\left(-3\right)\left(-4\right)\left(-5\right)....\left(-1999\right)\left(-2000\right)}{4.5.6.....2000.2001}\)

\(=\dfrac{\left(-3\right).\left(-1\right)}{2001}=\dfrac{3}{2001}\)

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