Câu hỏi của Tuyết Nhi Melody

Question

Tìm x :

$\dfrac{1}{3}x-\dfrac{1}{2}=\dfrac{3}{4}x+\dfrac{1}{15}$

$\left(x-\dfrac{2}{9}\right)^3=\left(\dfrac{2}{3}\right)^6$

Mk đang cần gấp lắm xin hãy giúp mk làm ơn

Đời về cơ bản là buồn...... · Accepted Answer

a) $\dfrac{1}{3}x-\dfrac{1}{2}=\dfrac{3}{4}x+\dfrac{1}{15}$

$\Rightarrow\dfrac{1}{3}x-\dfrac{3}{4}x=\dfrac{1}{2}+\dfrac{1}{15}$

$\Rightarrow\dfrac{4}{12}x-\dfrac{9}{12}x=\dfrac{15}{30}+\dfrac{2}{30}$

$\Rightarrow\dfrac{-5}{12}x=\dfrac{17}{30}$

$\Rightarrow x=\dfrac{-102}{75}$Câu trả lời: a) $\dfrac{1}{3}x-\dfrac{1}{2}=\dfrac{3}{4}x+\dfrac{1}{15}$

$\Rightarrow\dfrac{1}{3}x-\dfrac{3}{4}x=\dfrac{1}{2}+\dfrac{1}{15}$

$\Rightarrow\dfrac{4}{12}x-\dfrac{9}{12}x=\dfrac{15}{30}+\dfrac{2}{30}$

$\Rightarrow\dfrac{-5}{12}x=\dfrac{17}{30}$

$\Rightarrow x=\dfrac{-102}{75}$

Đời về cơ bản là buồn...... · Answer

$\left(x-\dfrac{2}{9}\right)^3=\left(\dfrac{2}{3}\right)^6$

$\Rightarrow\left(x-\dfrac{2}{9}\right)^3=\dfrac{64}{729}$

$\Rightarrow x-\dfrac{2}{9}=\dfrac{4}{9}$

$\Rightarrow x=\dfrac{2}{3}$Câu trả lời: $\left(x-\dfrac{2}{9}\right)^3=\left(\dfrac{2}{3}\right)^6$

$\Rightarrow\left(x-\dfrac{2}{9}\right)^3=\dfrac{64}{729}$

$\Rightarrow x-\dfrac{2}{9}=\dfrac{4}{9}$

$\Rightarrow x=\dfrac{2}{3}$

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